X^2-10x-95=0

Solution for X^2-10x-95=0 equation:

X^2-10X-95=0

a = 1; b = -10; c = -95;
Δ = b2-4ac
Δ = -102-4·1·(-95)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-4\sqrt{30}}{2*1}=\frac{10-4\sqrt{30}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+4\sqrt{30}}{2*1}=\frac{10+4\sqrt{30}}{2}
$